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550 V is applied to a 2700-pF capacitor. How much energy is stored?
given
V = 550 V
C = 2700 pF
= 2700*10^-12 F
Potential energy stored, PE = (1/2)*C*V^2
= (1/2)*2700*10^-12*550^2
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550V is applied to a 2600-pF capacitor. How much energy is stored? Express your answer using three significant figures and include the appropriate units.
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