Question

850 V is applied to a 2600 pF capacitor. How much energy is stored?

850 V is applied to a 2600 pF capacitor. How much energy is stored?
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Answer #1
Concepts and reason

The concept used to solve this problem is energy stored in the capacitor.

Use the potential difference and capacitance to find the energy stored in the capacitor.

Fundamentals

Expression for the charge is,

q=CV

Here, C is the capacitance, q is the charge, and V is the potential difference.

Expression for the element of energy stored is,

bpA= Пр

Here, is the element of energy stored, is the voltage, and charge element.

Expression for the charge is,

q=CV

Rearrange the equation to get the potential difference,

Expression for the element of energy stored is,

bpA= Пр

Substitute for V.

du =(4)44

Integrate the above equation,

[av = (3) dan

Substitute for Q in the above expression.

U=? (CV)
2c

Expression for the energy stored in capacitor is,

Substitute 850 V
for and 2600pF
for .

v = }(2600p})( 19 ) (ssov;
=9.3925x10J
=9.393x10 - J

Ans:

The energy stored in capacitor is 9.393x104)
.

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