Question

Suppose a memory manager employs paging with page size of 4 Kbytes. It has a memory of 256 Mbytes. A process of size 25 Kbytes needs to be loaded into memory. Answer the following. (a) How many frames are there in the memory? (b) How many bits are necessary to represent the physical address as <frame#, offset>? (c) How many frames need to be allocated to the process?

Answer 1

Siven hat byees 4 K page Size 4K bytes Page Si3e 2 = l092 12 biES bytes 20 2 bytes 256 x by teg 2O 28 bytes to heeded bytes are heorurw 28 Faudaffo memory ize frane ize 20 256x 2 2 20 256 2 256x2 6 ramay 2 16 bitegh2odecd

aHoas many fromey 7n he memery heir are the memory frames f in hu frames 2S6X 2 to represents tte Hous many bits are he pPh.sica memery 12> 16, 12 bits foY bits for frarm no, 61 () Houmany frames heeded to be allo cated to the Process 25k byteg Process momang f1ame S2a 4-kbytes oceuaw fo 9/V frane 3e 25byfes 4R bytes 6.23 ranes frome Aeaded