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CIRCLE THE MORE ACTIVE WHERE INDICATED st experiment is strictly a demonstration and must be done by your instructor. The students must wear their safety goggles, and must wear their safety goggles, and they must stay very far from the demonstrum аrеа. A small piece of sodium metal and water (a small volume of water in a large beaker covered by a wire gauze). Na + H20 The More Active? Na H 2. Zinc metal and magnesium sulfate solution Zn + MgSO The More Active? Zn Mg 3. Zinc metal and lead (II) nitrate solution Zn + Pb(NO3)2 The More Active? Zn Pb 4. Zinc metal and 3M sulfuric acid solution Zn + H2SO4 The More Active? Zn H The More Active? Cu H The More Active? Cu Ag 5. Copper metal and 3M sulfuric acid solution Cu + H2SO4 6. copper metal and silver nitrate solution Cu + AgNO 7. Lead metal (clean its surface) and cupric nitrate solution Pb + Cu(NO3)2 8. Lead metal (clean its surface) and sulfuric acid solution Pb + HSO The More Active? Pb Cu The More Active? PbH Conclusion: Make an activity series list for the elements used in your experiment starting with the most active first. The elements you used were H, Na, Mg, Cu, Pb, Ag, Zn. Discuss your reasoning. Least active Most active

Answer 1

Na +2 H2O --> 2NaOH + H2 ..more reactive = Na

Zn + MgSO4 ---> No reaction .. more reactive = Mg

Zn + PB(NO3)2 --> Zn(NO3)2 + Pb .. more reactive = Zn

Zn + H2So4 --> ZnSO4 + H2 ''more reactive =Zn

Cu+ H2SO4 ---> no reaction more reactive = H

Cu+ 2AgNO3--> Cu(NO3)2 + Ag.. more reactive = Cu

Pb + Cu(NO3)2--> No reaction -- more reactive = Pb

Pb + H2So4 --> PbSo4 +H2 ..more reactive =Pb
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reactivity series from most to least reactive

Na > Mg > Zn > Pb >H >Cu >Ag .
this is because the more reactive metals can replace metals from its salt which are
less reactive.
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Thank you.