Draw the final product from the following six-step reaction sequence.

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Draw the final product from the following six-step

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Answer 1

Answer #1

base 00 H30. R-X ソ0R-...O OR-X.RO WTo,RO RO OR -x RO OR CO2, ROH OR malonic ester R This is malonic ester synthesis

So following the scheme above you delocalize electrons with the base (Methoxide, -OCH3, is acting like a base) and add the brominated alkyl group to the center carbon to produce the following.

uploaded image Compound after Step 2

Treatment by another base should displace Br from the compound to produce

uploaded image Compound after Step 3

LiAlH4 will then reduce all carbonyl bonds

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This is as far as I got in the time I had left, hope this helps you on your way!

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Answer 2

Answer #2

media%2Fd31%2Fd3192a16-fe32-4126-ab25-d0

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Answer 3

Answer #3

The Br thing adds to the middle as above, but when more base is used in step 3, the Br on the other side attaches, forming a ring. LiAlH4/H2O changes the ketones into alcohols, which allows for the acetal formation in step 6.

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Answer 4

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Draw the final product from the following six-step reaction sequence.

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