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A man of mass m is standing on a bridge h meters high. The man is...

A man of mass m is standing on a bridge h meters high. The man is l m tall and he has a bungee chord attached to him that is L m long. The man bungee jumps of the bridge so that he just "kisses" the water below. The chord stretches x m. Form an equation for the height. (hint: you will use the quadratic equation and spring constant)

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Answer #1

so after falling L meter kinetic energy will convert into springs potential energy

so

(1/2)mv2 = (1/2) kx2

man is Ju ho o7 nv 2.

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