Question

As a result of a hypothetical reaction of A B that took place in a styruloam cp calorimete, the temperature of a 100 g of the solution in the calorimeter was measured to be 3 temperature of the solution was 1S C. The specilic heat of solution is 418 JrC The hoat cpcity the cup is 10 JC 2-1. Calculate the amount of heat released (or absorbed) as a result of this reaction (calculate g Refer to page 8 if you don't know how to calculate qthe amount of heat released or absorbed as a result of the reaction (1 hope you don't even need to refer to page 8 any more because you now become an espert on this 2-2. Was this reaction exothermic or endothermic? Justify your answer. 2-3.0.1 mol of A is assumed to be involved in the hypothetical reaction. Calculate the enthalpy change of the reaction, AH in J/mol. Explain why you finally need to report not by but by MH

Answer 1

The wrapped heat is calculated:

q = m * cp * ΔT Ccal * ΔT = 100 g * 4.18 * (15 - 5) ° C + 10 * (15-5) = 4280 J

The reaction is exothermic, since the temperature of the solution increased.

The enthalpy of reaction is calculated:

ΔH = - q / n = - 4280 / 0.1 = 42800 J / mol

If you liked the answer, please rate it in a positive way, you would help me a lot, thank you.