Question

The Claisen condensation converts 2 molecules of an ester into a ?-keto ester. The reaction starts...

The Claisen condensation converts 2 molecules of a

The Claisen condensation converts 2 molecules of an ester into a ?-keto ester. The reaction starts with the ester in an alkoxide/alcohol solution and is worked up with acid to form the neutral ?-keto ester product.


Step 3. Draw the ester-containing intermediate produced from step 2 and draw the next reactant or reagent, if applicable. Add curved arrows.





Step 4. Draw the ester-containing intermediate produced from step 3 and draw the next reactant or reagent, if applicable. Add curved arrows.



Step 5. Draw the ester-containing intermediate produced from step 4 and draw the final reagent, H3O . Add curved arrows.

The Claisen condensation converts 2 molecules of a


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Answer #1
Concepts and reason

The Claisen condensation is a reaction between any two esters or an ester and a carbonyl in the presence of a strong base that leads to a new carbon-carbon bond formation in the product. Generally, in this type of condensation reaction, a carbanion is the intermediate. A carbanion is generated when a proton is abstracted from the ester by the base.

Fundamentals

• Curved arrow mechanism: Curved arrow mechanism explains how the reaction is proceeding and the clear transfer of electrons. In this curved arrow, two parts are there: (1) Head (2) Tail.

• Head indicates the destination of electron pair while the tail part indicates the excess electron pair on a molecule or a pi bond.

tail
electron pair
donor group
head
electron pair
accepting group

• Curved arrow always indicates the electron flow path in the reaction mechanism. That is, a curved arrow directed towards positive charge or electron deficient site from the electron cloud.

• General Claisen condensation reaction is depicted below:

R2
Base
R1
R2
Но
о
о

Given reaction is drawn below:

1. CH,CH2&
(CH3CH2OH
+
ОН
2. H30
о
о

Ethoxide is strong base, and it abstracts the acidic proton from substrate that leads to carbanion intermediate.

н
Н.
н
CH3CH20
о
т
т

Produced carbanion intermediate reacts with one more ester to give condensed product.

н
Н.
н
Н.
о:
н
Н
Н
Н.

Ethoxide elimination from oxyanion is depicted below:

Н
+
-I
I

Due to the basic nature of ethoxide ion, it abstracts the proton from the active methylene part of

the product.

+ Но
н

On protonation to the carbanion intermediate:

НаО
Н-О
Н
Н
о
о

Ans:

The complete curved arrow mechanism is shown below:

Н
СH,CH,0
н
н
н
Н
н
н
Н
н
н
н
н
+ но
Н
Н,о
+ H.О
Н
Н
Н
о.

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