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6 Sample Final-exam.pdf S No Shde Title anie Portfolio E-Leaning Moodle | Ge X x x x ng.gju.edu.jo/pluginfile.php/142960/mod
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Answer #1

Let,

x1 = number of Model I to be produced
x2 = number of Model II to be produced
x3 = number of Model III to be produced

Objective is ton maximize profit so objective function = Max 30x1+20x2+50x3

Subject to,

2x1+3x2+5x3 <= 4000 (raw material - A)
4x1+2x2+7x3 <= 6000 (raw material - B)

Minimum demand
x1>= 200
x2>= 200
x3>= 150

Ratio requirement

x1 = 2k,x2 = 3k and x3 = 5k

so, x1/2 = x2/3

or, 3x1-2x2 = 0

x2/3 = x3/5

or, 5x2 - 3x3 = 0

Labor force constraint

x1+1/2x2+1/3x3 <= 1500 [as labor force is equivalent with 1500 units of model I]

or, 6x1+3x2+2x3 <= 9000

x1,x2,x3 >= 0 (Non-negativity constraint)


Solving in solver we get,

x1 = number of Model I to be produced = 210.5263 = 211 (Rounded to nearest whole number as number of model I is an integer)
x2 = number of Model II to be produced = 315.7895 = 316 (Rounded to nearest whole number as number of model II is an integer)
x3 = number of Model III to be produced = 526.3158 = 526  (Rounded to nearest whole number as number of model III is an integer)

and maximized profit = 38947.37

Solver screenshot

x1

x2

x3

210.5263

315.7895

526.3158

Objective function

38947.37

raw material - A

2

3

5

4000

<=

4000

raw material - B

4

2

7

5157.895

<=

6000

(Minimum demand - Model I)

1

210.5263

>=

200

(Minimum demand - Model II)

1

315.7895

>=

200

(Minimum demand - Model III)

1

526.3158

>=

150

Ratio requirement

3

-2

-1.1E-13

=

0

Ratio requirement

5

-3

4.55E-13

=

0

labor force constraint

6

3

2

3263.158

<=

9000

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