Question

HW Score: 60% , 6 of 10 pts UReview 7-47 (book/static) Question Help In American football, the playing field is 53.33 yards [yd] wide by 120 yards lyd) long. For a special game, the field staff want to paint the playing field orange. Of course, they will use biodegradable paint available for purchase in 25-gallon (gal] containers. If the paint is applied in a thickness of 1.2 mllimeters [mmj in a uniform layer, how many containers of paint will they need to purchase? EClick the icon to view conversion table for length and volume. The field staff need to purchase 67.85 containers. (Round your answer up to the nearest whole number.)

please show the work for this question.

Answer 1

We know 1 yard = 0.9144 m

Then length of football field = 120 yards = 120 x 0.9144 m = 109.728 m

Width of football field = 53.33 yards = 53.33 x 0.9144 m = 48.965 m

Thickness of paint = 1.2 mm = 1.2 x 10^-3 m

Then volume of paint required = 109.728 x 48.965 x ( 1.2 x 10^-3 ) = 6.45 m³

Now volume in one container of paint = 25 gallon = 25 x 0.0038m³ = 0.095 m³

Then number of containers required = 6.45 / 0.0946353 = 67.8 containers.