1-Chlorobutane (2.5 mL, d=0.886) in 20 mL of acetone is reacted with 90 mL of a 15 wt% solution of NaI in acetone. After work-up, you obtain 1.3 g of 1-iodobutane. which is the limiting reagent and what is your % yield?
1-Chlorobutane (2.5 mL, d=0.886) in 20 mL of acetone is reacted with 90 mL of a...
2-bromobutane (3.0 ml) in 25 ml of acetone reacts with 80 ml of a 20 wt% solution of Nal in acetone. After work up, you obtain 3.9 g of 2-iodobutane. What is the limiting reagent and percent yield of this reaction? Why when finding the mass of Nal in acetone do you use the density of acetone and not Nal?
1. In both the sodium iodide
test and the silver nitrate test, why does 2-bromobutane react
faster than 2-chlorobutane?
Bromine is a better leaving group since it is a weaker base than
chlorine is.
2. a. Why does benzyl chloride react under both
SN1 and SN2 conditions?
Benzyl
chloride is a primary alkyl halide, hence reactive under SN2
conditions.
The
primary carbocation formed due to the departure of Cl- is
stabilized by the pi electrons in the benzene ring.
b. Why is...
consider an experiment in which 50.0 ml of 0.090 M Strontium
nitrate was reacted with 45.0 ml of 0.100 M potassium iodate.
calculate the number of moles of the reagent
13. (20 points) Given: Sr(NO): + 2 Kio, → Sr(10h + 2 KNO) NE214 38 1. う , Consider an experiment in which 50.0 mL of 0.090 M Strontium nitrate was reacted with 45.0 mL of0.100 moles of each reagent. SHOW ALL woRK(24 12 um iodate. Calculate the number of...
2 dibenzalacetone acetone benzaldehyde MW- 106.13 g/mol bp-1 78°C d 1.04 g/mL MW 234.30 g/mol mp #110-1110 MW-58.08 g/mol bp 56°C d 0.79 g/mL Its bs Reaction Setup (3 pts) S. OS Initial quantity of NaOH: S. I Initial quantity of benzaldehyde: mL Initial quantity of acetone: mL Theoretical yield of dibenzalacetone based on benzaldehyde: (show calculations) Theoretical yield of dibenzalacetone based on acetone 9 (show calculations) ce tone Limiting Reagent: Product Data (10 pts) fivAL Mass: 3.3g Percent Yield:...
Name Prelaboratory Assignment 9 (25 pts) 1. A sample of 0.72 g of Al is reacted with 17.0 mL of 2.4 M KOH. Which one is the limiting reagent? SHOW WORK 9 pts 2Al (s)+ 2KOH (aq) + 6 H2O ()-2KAI(OH), (aq)+ 3 H: (g) 2. If a salt has a solubility of 27.2 g/100 mL water at 25 °C, what volume of water would be needed to dissolve 12.4 g of the salt? 6 pts 3. Calculate the theoretical...
just need answer, which letter.
TAL 1. (20pts) A student reacted 4.0 g of 2-hydroxybenzoic acid (C H6O3, MW 138 g/mol) with 4.0 mL of acetic anhydride (CH603, MW 102 g/mol) and 1 g of concentrated sulfuric acid.(MW 98) After workup, the student isolated 2.5 g of aspirin (MW 180). The density of acetic anhydride is 1.08 g/mL. (atomic weights: C. 12, H 1; 0, 16, S. 32) 1a. The limiting reagent is a) 2-hydroxybenzoic acid b) acetic anhydride c)...
Name Prelaboratory Assignment 9 (25 pts) 1. A sample of 0.72 g of Al is reacted with 17.0 mL of 2.4 M KOH. Which one is the limiting reagent? SHOW WORK! 9 pts 2Al(s) + 2KOH (aq) + 6 H20 (1) ► 2KAl(OH)4 (aq) + 3 H2 (8) 2. If a salt has a solubility of 27.2 g/100 mL water at 25 °C, what volume of water would be needed to dissolve 12.4 g of the salt? 6 pts 3....
What is the limiting reagent and theoretical yield? (please show work step by step with units) This is an aldol reaction with acetone, benzaldehyde, NaOH (5M in 25 mL solution = 5g), and an ethanol solvent. There is a 2:1 ratio of benzaldehyde and acetone. 3g of acetone which I calculated to be .05 moles . Since it was 2:1 I assumed that meant there needed to be 0.10 moles of benzaldehyde that I calculated to be 10.16 g.
16. A student reacted 0.7655 g of chromium (at. wt = 51.996 g/mol) with exactly 1.566 g of chlorine (at. wt. -- 35.453 g/mol). Convert both these masses to moles and determine the empirical formula (like A,X,) of the compound of Cr and CI. SHOW YOUR WORK 17. In a chemical reaction, the substance which gets used up first (or runs out first) is called the _(write in the correct words). 18. In a chemical reaction, the maximum amount of...
6. Please fill this table completely Molar equiv. Substance Water Pentane Acetone d (g/mL) 0: 997 0.626 0.784 TEMPO M. Wt. (g/mol) 18.02 72.15 58.08 156.25 156,19 143.45 82.10 201.06 0.96 Amount 25ML 25 mL 15 mL 40 mg 40mg 25 mg 4 dropš 2.5 mmol 11.03 approx Bipyridine CuBr NMI Starting alcohol: (4-bromophenylmethanol Product aldehyde: 4-bromobenzaldehyde 1.44 185.02 1.85