2-bromobutane (3.0 ml) in 25 ml of acetone reacts with 80 ml of a 20 wt%...
2-bromobutane (3.0 ml) in 25 ml of acetone reacts with 80 ml of a 20 wt% solution of Nal in acetone. After work up, you obtain 3.9 g of 2-iodobutane. What is the limiting reagent and percent yield of this reaction? Why when finding the mass of Nal in acetone do you use the density of acetone and not Nal?
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2-bromobutane (3.0 ml) in 25 ml of acetone reacts with 80 ml of
a 20 wt%...
1-Chlorobutane (2.5 mL, d=0.886) in 20 mL of acetone is reacted with 90 mL of a...
1-Chlorobutane (2.5 mL, d=0.886) in 20 mL of acetone is reacted with 90 mL of a 15 wt% solution of NaI in acetone. After work-up, you obtain 1.3 g of 1-iodobutane. which is the limiting reagent and what is your % yield?
find limiting reagent? acetone 3.63 mL benzaldehyde 10.5mL bp (°C) mol. wt. (g/mole) 58.08 density (g/mL)...
find limiting reagent?
acetone 3.63 mL
benzaldehyde 10.5mL
bp (°C) mol. wt. (g/mole) 58.08 density (g/mL) 0.791 56 106.23 178-179 1.044 Acetone Benzaldehyde NaOH Dibenzalacetone 40.00 234.30 mp 110-111 9. Calculations for synthesis-moles of reactants, limiting reagent, theoretical yield , % experimental yield, show all math
1. In both the sodium iodide test and the silver nitrate test, why does 2-bromobutane react faster...
1. In both the sodium iodide
test and the silver nitrate test, why does 2-bromobutane react
faster than 2-chlorobutane?
Bromine is a better leaving group since it is a weaker base than
chlorine is.
2. a. Why does benzyl chloride react under both
SN1 and SN2 conditions?
Benzyl
chloride is a primary alkyl halide, hence reactive under SN2
conditions.
The
primary carbocation formed due to the departure of Cl- is
stabilized by the pi electrons in the benzene ring.
b. Why is...
Compound molar mass density volume mmol equ 21% sodium ethoxide in ethanol 68.05 g/mol 0.868 g/mL...
Compound molar mass density volume mmol equ 21% sodium ethoxide in ethanol 68.05 g/mol 0.868 g/mL 20 mL ~1.3 *1-bromobutane 137.02 g/mol 1.276 g/mL 4.5 mL ~1.0 *Limiting Reagent: 1-bromobutane I need help finding the mmol of sodium ethoxide in ethanol and 1-bromobutane. Also how to find the theoretical yield of this reaction from this graph?
A precipitation reaction occurs when 749 mL of 0.846 M Pb(NO3)2 reacts with 375 mL of...
A precipitation reaction occurs when 749 mL of 0.846 M Pb(NO3)2 reacts with 375 mL of 0.810 M KI, as shown by the following equation. Pb(NO3)2(aq) + 2 Kl(aq) – PbL,(s) + 2 KNO, (aq) Identify the limiting reactant. O Pb(NO3)2 ОРЫ, OKI O KNO, Calculate the theoretical yield of Pol, from the reaction. mass of Pble: Calculate the percent yield of Pbl, if 50.6 g of Pol, are formed experimentally. percent yield of Pbl Suppose 57.2 mL of a...
Suppose 57.4 mL of a 0.101 M solution of Na, S04 reacts with 147 mL of...
Suppose 57.4 mL of a 0.101 M solution of Na, S04 reacts with 147 mL of a 0.333 M solution of MgCl, to produce MgSO4 and NaCl as shown in the balanced reaction. Na, SO4(aq) + MgCl, (aq) + MgSO4(s) + 2 NaCl(aq) Determine the limiting reactant for the given reaction. MgCl2 Na S04 MgSO4 NaCl Calculate the mass of MgSO, that can be produced in the given reaction. mass of MgSO4 Only 0.421 g of MgSO4 are isolated after...
Suppose 60.8 mL of a 0.136 M solution of Na2SO4 reacts with 161 mL of a...
Suppose 60.8 mL of a 0.136 M solution of Na2SO4 reacts with 161 mL of a 0.238 M solution of MgCl2 to produce MgSO4 and NaCl as shown in the balanced reaction.Na2SO4(aq)+MgCl2(aq)⟶MgSO4(s)+2NaCl(aq) Determine the limiting reactant for the given reaction. MgSO4 Na2SO4***** NaCl MgCl2 Calculate the mass of MgSO4 that can be produced in the given reaction. mass of MgSO4: g Only 0.430 g of MgSO4 are isolated after carrying out the reaction. Calculate the percent yield of MgSO4. percent...
Suppose 83.2 mL of a 0.134 M solution of Na,SO reacts with 123 mL of a...
Suppose 83.2 mL of a 0.134 M solution of Na,SO reacts with 123 mL of a 0.329 M solution of MgCl, to produce MgSO and NaCl as shown in the balanced reaction Na,SO4 (aq)MgCl2 (aq) MgSO4(s)2 NaCl(aq) Determine the limiting reactant for the given reaction. O MgCl2 MgSO O Na,SO4 O NaCl Calculate the mass of MgSO4 that can be produced in the given reaction mass of MgSO4 1.384 g Only 0.335 g of MgSO, are isolated after carrying out...
2 dibenzalacetone acetone benzaldehyde MW- 106.13 g/mol bp-1 78°C d 1.04 g/mL MW 234.30 g/mol mp #110-1110 MW-58.08 g/mol bp 56°C d 0.79 g/mL Its bs Reaction Setup (3 pts) S. OS Initial quant...
2 dibenzalacetone acetone benzaldehyde MW- 106.13 g/mol bp-1 78°C d 1.04 g/mL MW 234.30 g/mol mp #110-1110 MW-58.08 g/mol bp 56°C d 0.79 g/mL Its bs Reaction Setup (3 pts) S. OS Initial quantity of NaOH: S. I Initial quantity of benzaldehyde: mL Initial quantity of acetone: mL Theoretical yield of dibenzalacetone based on benzaldehyde: (show calculations) Theoretical yield of dibenzalacetone based on acetone 9 (show calculations) ce tone Limiting Reagent: Product Data (10 pts) fivAL Mass: 3.3g Percent Yield:...
A precipitation reaction occurs when 737 ml of 0.962 M Pb(NO,), reacts with 321 mL of...
A precipitation reaction occurs when 737 ml of 0.962 M Pb(NO,), reacts with 321 mL of 0.806 M KI, as shown by the following equation. Pb(NO3)2(aq) + 2 Kl(aq) — PbL,(s) + 2 KNO, (aq) Identify the limiting reactant. Phl, KNO, Pb(NO3)2 OKI Calculate the theoretical yield of Pbl, from the reaction mass of Phle: Calculate the percent yield of Pbl, if 53.2 g of Pbl, are formed experimentally percent yield of Pbl
find limiting reagent?
acetone 3.63 mL
benzaldehyde 10.5mL
bp (°C) mol. wt. (g/mole) 58.08 density (g/mL) 0.791 56 106.23 178-179 1.044 Acetone Benzaldehyde NaOH Dibenzalacetone 40.00 234.30 mp 110-111 9. Calculations for synthesis-moles of reactants, limiting reagent, theoretical yield , % experimental yield, show all math
1. In both the sodium iodide
test and the silver nitrate test, why does 2-bromobutane react
faster than 2-chlorobutane?
Bromine is a better leaving group since it is a weaker base than
chlorine is.
2. a. Why does benzyl chloride react under both
SN1 and SN2 conditions?
Benzyl
chloride is a primary alkyl halide, hence reactive under SN2
conditions.
The
primary carbocation formed due to the departure of Cl- is
stabilized by the pi electrons in the benzene ring.
b. Why is...
A precipitation reaction occurs when 749 mL of 0.846 M Pb(NO3)2 reacts with 375 mL of 0.810 M KI, as shown by the following equation. Pb(NO3)2(aq) + 2 Kl(aq) – PbL,(s) + 2 KNO, (aq) Identify the limiting reactant. O Pb(NO3)2 ОРЫ, OKI O KNO, Calculate the theoretical yield of Pol, from the reaction. mass of Pble: Calculate the percent yield of Pbl, if 50.6 g of Pol, are formed experimentally. percent yield of Pbl Suppose 57.2 mL of a...
Suppose 57.4 mL of a 0.101 M solution of Na, S04 reacts with 147 mL of a 0.333 M solution of MgCl, to produce MgSO4 and NaCl as shown in the balanced reaction. Na, SO4(aq) + MgCl, (aq) + MgSO4(s) + 2 NaCl(aq) Determine the limiting reactant for the given reaction. MgCl2 Na S04 MgSO4 NaCl Calculate the mass of MgSO, that can be produced in the given reaction. mass of MgSO4 Only 0.421 g of MgSO4 are isolated after...
Suppose 83.2 mL of a 0.134 M solution of Na,SO reacts with 123 mL of a 0.329 M solution of MgCl, to produce MgSO and NaCl as shown in the balanced reaction Na,SO4 (aq)MgCl2 (aq) MgSO4(s)2 NaCl(aq) Determine the limiting reactant for the given reaction. O MgCl2 MgSO O Na,SO4 O NaCl Calculate the mass of MgSO4 that can be produced in the given reaction mass of MgSO4 1.384 g Only 0.335 g of MgSO, are isolated after carrying out...
2 dibenzalacetone acetone benzaldehyde MW- 106.13 g/mol bp-1 78°C d 1.04 g/mL MW 234.30 g/mol mp #110-1110 MW-58.08 g/mol bp 56°C d 0.79 g/mL Its bs Reaction Setup (3 pts) S. OS Initial quantity of NaOH: S. I Initial quantity of benzaldehyde: mL Initial quantity of acetone: mL Theoretical yield of dibenzalacetone based on benzaldehyde: (show calculations) Theoretical yield of dibenzalacetone based on acetone 9 (show calculations) ce tone Limiting Reagent: Product Data (10 pts) fivAL Mass: 3.3g Percent Yield:...
A precipitation reaction occurs when 737 ml of 0.962 M Pb(NO,), reacts with 321 mL of 0.806 M KI, as shown by the following equation. Pb(NO3)2(aq) + 2 Kl(aq) — PbL,(s) + 2 KNO, (aq) Identify the limiting reactant. Phl, KNO, Pb(NO3)2 OKI Calculate the theoretical yield of Pbl, from the reaction mass of Phle: Calculate the percent yield of Pbl, if 53.2 g of Pbl, are formed experimentally percent yield of Pbl
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