A large punch bowl holds 3.00 kg of lemonade (which is essentially water) at 23.0 ∘C....

Question

Question

A large punch bowl holds 3.00 kg of lemonade (which is essentially water) at 23.0 ∘C. A 5.70×10−2-kg ice cube at -10.0 ∘C is placed in the lemonade.

Part A:

What is the final temperature of the system? Ignore any heat exchange with the bowl or the surroundings. (degrees C)

Part B:

What is the amount of ice (if any) remaining?

Express your answer using one significant figure. (kg)

Answer 1

Answer #1

al temperature. Water-ia is T. Heat gainnd by ce Heat lost M Cs(23-T) 3 (4180 し23-T ニ 2 355000 + 4180T = 52-68 x4180 X23 -「ニ20.980 dag

Please let me know if it was helpful. Thank you!

Answer 2

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