Question

a system consisted of two objects sitting on a floor, a 15 kg object on top with a 12 kg object at the bottom. the sliding coefficient of friction between the two objects was 0.3. the floor sliding coefficient of friction was 0.2. determine the force applied to the 12 kg bottom object such that both objects had 0.5 m/s/s acceleration.

Answer 1

Since both the blocks are moving with the same acceleration, it means that there is no slipping between the blocks. So, the force applied will be:

F = (m1 + m2)*a

= (15 + 12)*0.5

= 13.5 N