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A 70.0kg archer, standing on frictionless ice, shoots a 200g arrow at a speed of 200m/s...

A 70.0kg archer, standing on frictionless ice, shoots a 200g arrow at a speed of 200m/s . What is the recoil speed of the archer?

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Answer #1

conserving momentum


m1v1=m2v2


==>0.2*200=70*v2


==> velocity of man = 0.5714 m/s

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