Question

7201 total cakclum tests gave the following readings (in mgjal). Assume that the population of x values has an appreximately normal dstribution. total calcium level below 6 mg/di Recently, the patient's 91 9.2 10.7 85 94 9.8 10.0 9.9 112 121 (a) Use a calculator with mean and sample standard deviation keys to find the sample mean reasirg x and the sample standand devition x-9.99 s (Round your anewers to two decimal places) (b) Find a 99.9% co lower lime upper lit dence interval for the population mean of tetel tha peteres bood (Reund your anwer to two calor" Rosed on your results in part (b), de you think tis patient sle has a cokiun deficiency?Explan O Yes. This confidence interval supgests that the patient may stitil have a calcium det cleney O Yes. This confidence interval suggests that the patent no O No. This confidence interval suggests that the patiene may stal have a cakcium deficiency O No. Thes confieren irtervai suggests that the patient no has a calon defreey ionger has & caloium deficiency

Answer 1

1) sample size n 10 90% confidence interval for population mean Given X- 9.99 s = 1.08 n 10 Sample Mean Population Standard Deviation Sample Size Confidence interval for mean is given by For 99.9%, α = 0.001, a/2 = 0.0005 From the z-tables, or Excel function NORMS. INV(α/2) z NORM.S.INV(0.05) - 3.291 (We take the positive value for calculations) 1.08 = 9.99± 3.291 * = (8.866, 11.114) = (8.87, 11.11) 99.9% confidence interval is (8.87, 11.11) V10 (Rounding to two decimals) uden Above Conidence interval is found usina z-distribution f we use t-dist, the confidence interval obtained is (8.88, 11.10) Pi ease check what you need to use accoraing to your curriculum and enter the aswer c) Since the mean of the sample is within the 99.9% confidence interval, the patient no longer has calcium deficiency Answer: No. The confidence interval suggests that the patient no longer has a calcium deficiency