Hi,You've hung two very large sheets of plastic facing each other with distance d between them, as shown in Figure P26.50 ( http://i137
You've hung two very large sheets of plastic facing each other with distance d between them, as shown in Figure P26.50 ( http://i137.photobucket.com/albums/q208/infinitbelt/p26-50-1.gif ). By rubbing them with wool and silk, you've managed to give one sheet a uniform surface charge density n1 = -4(n0) and the other a uniform surface charge density n2 = 5(n0). What is the electric field vector at points 1, 2, and 3?
I drew the force diagrams for the three points but that is where I think I am making my mistake. For example, for point 1, I have a force going to the left from the positive plate and a force going to the right from the negative plate. The difference I get is 1(n0), but that is wrong. Any ideas?
Thanks!
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Hi,You've hung two very large sheets of plastic facing each other with distance d between them, as shown in Figure P26.50 ( http://i137
Problem 23.20 You've hung two very large sheets of plastic facing each other with distance d...
Problem 23.20 You've hung two very large sheets of plastic facing each other with distance d between them, as shown in the figure (Figure 1). By rubbing them with wool and silk, you've managed to give one sheet a uniform surface charge density Th no and the other a uniform surface charge density T2 +3no. Figure 1 of 1 Part A What is the electric field vector at point 1? In the space provided, enter the numerical factor that multiplies...
The two plates are a distance D apart. The surface area of the face of each...
The two plates are a distance D apart. The surface area of the
face of each plate is A, the total charge on each plate is
+Q and ?Q, and the resulting uniform charge
density is +?0 and ??0
respectively so that
?0=Q/A.
Use the principle of superposition to identify the correct
statement(s) about the electric field at points 1,2,3, and 4.
The field at points 1 and 4 will be zero because the fields from
positively and negatively plates...
Two very large, nonconducting plastic sheets, each 10.0 cm thick, carry uniform charge densities σ1, σ2, σ3 and σ4 on their surfaces, as shown in the following figure (Figure 1)
Two very large, nonconducting plastic sheets, each 10.0 cm
thick, carry uniform charge densities σ1, σ2, σ3 and σ4 on their
surfaces, as shown in the following figure (Figure 1) . These
surface charge densities have the values σ1 = -7.50 μC/m2 ,
σ2=5.00μC/m2, σ3 = 1.30μC/m2 , and σ4=4.00μC/m2. Use Gauss's law
to find the magnitude and direction of the electric field at the
following points, far from the edges of these sheets.What is the magnitude of the electric field at...
Problem 23.20 You've hung two very large sheets of plastic facing each other with distance d between them, as shown in the figure (Figure 1). By rubbing them with wool and silk, you've managed to give one sheet a uniform surface charge density Th no and the other a uniform surface charge density T2 +3no. Figure 1 of 1 Part A What is the electric field vector at point 1? In the space provided, enter the numerical factor that multiplies...
The two plates are a distance D apart. The surface area of the
face of each plate is A, the total charge on each plate is
+Q and ?Q, and the resulting uniform charge
density is +?0 and ??0
respectively so that
?0=Q/A.
Use the principle of superposition to identify the correct
statement(s) about the electric field at points 1,2,3, and 4.
The field at points 1 and 4 will be zero because the fields from
positively and negatively plates...
Two very large, nonconducting plastic sheets, each 10.0 cm
thick, carry uniform charge densities σ1, σ2, σ3 and σ4 on their
surfaces, as shown in the following figure (Figure 1) . These
surface charge densities have the values σ1 = -7.50 μC/m2 ,
σ2=5.00μC/m2, σ3 = 1.30μC/m2 , and σ4=4.00μC/m2. Use Gauss's law
to find the magnitude and direction of the electric field at the
following points, far from the edges of these sheets.What is the magnitude of the electric field at...
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