Question

2: If you squeeze 24.75 g of lemon juice from a lemon and it requires 15.45 mL of 0.00115 M KIO3 to reach the endpoint. What is the concentration of Vit C in mg per gram of juice (mg/g)? Mol KIO3/g juice = Mol Vit C/g juice = mg Vit C/g juice = 3 If you titrate 25.00 ml of a 460 mg/L ascorbic acid solution, boil it for 15 minutes and then titrate it with 10.75 mL of 0.00135 M KIO3. What is the concentration of Vitamin C in mg/g ascorbic acid ( original) (mg/g)? Mol KIO3/g ascorbic acid (original)= Mol Vit C/g ascorbic acid (original) mg Vit C/g ascorbic acid (original) = 4: And finally, If you boil 25.55 g of juice and then titrate it with 13.18 mL of 0.001 03M KIOs what is the concentration of vitamin C in mg per gram of juice (mg/g)? Mol KIO3/g juice Mol Vit C/g juice = mg Vit C/g juice=

can someone please help me with #2, 3 & 4. Could you also please show me step by step how you obtained the answer.

Thank you!

Answer 1

Riaction take ae To3 +5I + GHT 312+3H O Acob +T 21 dohydroasopbi alid auid fom seaiton il is clear thet / 3mol T,3md Asabi auid 1mol Io 2 Riquire 55 eo0015 msl O.o1776 75mhol To ascobi auid3 To3-3(0.01777 net

= 0.0533025 mol Vit-C Cascobicauid 24.75uca aquivad o.017765 mal 13 Jua - 7179 x1 mmd 7.179 x167 moiktoyleica-139 xls mol Contains 0.0533025mmol 2५ +5 - 2154 xlmmo = 2.154 xi mok 2.154 xlamo mot Vite mdco ma 176-12 glmol Vit-c 2. 154 xlebl x1964124 mg Vach ue _4 '8 =03343 mg Vit