Can someone help me with this. Thank you
Can someone help me with this. Thank you PRELAB 1. Calculate the volume of 6.0M NaOH...
2. Calculate the mass of KHP needed to react completely with 15 mL of a 0.10 M NaOH solution. Consider the reaction equation to be as shown below, molar mass of KHP is 204.3g/mol 3. Calculate the molarity of a solution of sodium hydroxide if 23.64 mL of this solution is needed to neutralize 0.5632 g of KHP. 4. It is found that 24.68 mL of 0.1165 M NaOH is needed to titrate 0.2931 g of unknown monoprotic acid to...
a. Calculate the volume of 0.450 M Ba(OH), which will be needed to neutralize 46,00 mL of 0.252 M HCI. b. Find the molar concentration of a sulfuric acid solution, 35.00 mL of which neutralizes 25.00 mL of 0.320 M NaOH. (Careful! Sulfuric acid is diprotic!) c. Calculate the "molarity of water" H₂O in pure water at 30°C. (Hint: The density of water at 30°C is 0.9957 g/mL.] d. A 15.00 mL sample of a solution of H₂SO₄ of unknown concentration was titrated with...
Any help would be great. thank you Calculate the molar concentration of an NaOH solution that required 15.81 mL to com- pletely neutralize 0.509 g of KHP (Remember that the "P" in KHP does not mean phos- phorus. See the molecular structure and molar mass of KHP given earlier in the lab.) 3. KHP(s)+NaOH(aq) -NaKP(aq) +H,O(e) Calculate the mass of KHP that will react completely with 25.00 mL of 0.1750 M NaOH 4. 5 Write the balanced equation for the...
Part A. Calculate the volume lf 0.210-M NaOH solution needed to completely neutralize 89.1 mL of a 0.310-M solution of the diprotic acid H2C2O4 Part B. You wish to make a 0.202 M Hydrochloric acid solution from a stock solution of 3.00 M hydrochloric acid. How much concdntrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution? Part C. an aqueous solution of barium hydroxide is standarized by titration with a 0.143 M...
2. How many mL of 0.100M NaOH would you need to titrate if you measured out 0.120 g of oxalic acid? Must show calculation. (5 pts) lying an unknown acid Objective: Identify an unknown diprotic acid by determining its molecular weight. Introduction: A diprotic acid is an acid that yields two H ions per acid molecule. Therefore, two moles of NaOH are need to react with every one mole of diprotic acid. The net reaction of a diprotic acid, H:X,...
1. A volume of ___ mL of 0.100 M NaOH(aq) is required to titrate 0.500 g of potassium hydrogen phthalate (often abbreviated KHP) to the endpoint. 2. A 0.5741 g sample of a monoprotic acid was titrated with 0.1008 M NaOH(aq). If 37.89 mL of sodium hydroxide solution were required for the titration, the molar mass of the monoprotic acid is ___ g/mol.
3. Calculate the molar concentration of an NaOH solution that required 15.81 ml to com pletely neutralize 0.509 g of KHP (Remember that the "P" in KHP does not mean phos- phorus. See the molecular structure and molar mass of KHP given earlier in the lab.) KHP(s) + NaOH(aq) - NaKP(aq) + H,O(C) 4. Calculate the mass of KHP that will react completely with 25.00 mL of 0.1750 M NaOH. 5. Write the balanced equation for the reaction that occurs...
How would kne slove for part C wjth the given data? DATA A. NaOH Preparation Volume of concentrated NaOH Molarity of concentrated NaOH 16 mL 6.0M 185 mL Volume of DI water B. NaOH Standardization Trial # 1 1.724, 2 3 1.956 9 1.8799 Mass of KHP Titration with NaOH: Initial buret reading 0.4 I mL 18.99mL 0.400 0.51 mL 20.98 m2 20.22 mb Final buret reading C. Molar Mass of NH X Salt UNKNOWN NUMBER: Mass of unknown 0-033...
D Question 1 2 pts 0.635g of NaOH was placed in a 250 mL volumetric flask and distilled water was added to the 250.00 mL mark. What volume of 0.231M sulfuric acid, in mL, is required to titrate a 25.00 mL aliquot of the NaOH solution? Round your answer to two decimal places. Molar Mass: Na 23.0 g/mol, S 32.1 g/mol, O 16.0 g/mol, H 1.0g/mol
5.5.1 1 of 1 NaOH Example 5.20 Calculate the molar mass of a monoprotic acid if it takes 349 mL of 0.5000 M NaOH to neutralize 25.00 mL of a solution of the unknown act 2 containing 3.172 g of the acid. HA + NaOH -> H2O + NA mmol Nools=0.5000 wind Hooh - Int Half solution 1 mool HA = 16.74 manol Noot x Immol 44 - = 16.74 mmd HD Immol Wool mdar mass of H A 3-172...