The UV-VIS spectrum of a CH2C12 solution of the gold(I) compound shown below with R=Ph is: λmax(ϵ) = 239 (92 500), 269 (67 000), 286 (72 000), 303 (28 000), 315 nm (21 000 dm3 mol-1 cm-1).
[Data: E.C. Constable et al. (2009) Eur. j. Inorg. Chem., p. 4710.]
(a) π*← π transitions contribute to Ihe observed spectrum. How do these arise?
(b) Is the compound coloured?
(c) You are asked to compare the UV-VIS spectra of a series of these compounds with different R substituents. Why should you compare plots of ϵ against λ rather than A against λ?
We need at least 10 more requests to produce the solution.
0 / 10 have requested this problem solution
The more requests, the faster the answer.