The same enzyme as in Problem 15 is studied in the presence of a different inhibitor (inhibitor B). In this case, two different concentrations of inhibitor are used. Data are as follows:
| v [ (mmol/L) min −1] | ||
[S] (mmol/L) | No inhibitor | 3mM inhibitor B | 5mM inhibitor B |
1.25 | 1.72 | 1.25 | 1.01 |
1.67 | 2.04 | 1.54 | 1.26 |
2.50 | 2.63 | 2.00 | 1.72 |
5.00 | 3.33 | 2.86 | 2.56 |
10.00 | 4.17 | 3.70 | 3.49 |
(a) What kind of inhibitor is inhibitor B?
(b) Determine the apparent Vmax and KMat each inhibitor concentration.
(c) Estimate KIfrom these data.
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