To decide whether two different types of steel have the same true average fracture toughness values, n specimens of each type are tested, yielding the following results:
Calculate the P-value for the appropriate two-sample z test, assuming that the data was based on n = 100. Then repeat the calculation forn = 400 . Is the small P-value for n = 400 indicative of a difference that has practical significance? Would you have been satisfied with just a report of the P-value? Comment briefly.
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