Problem

The reaction between a 1,2-ethanediamine solution of K4[Pb9] and a toluene solution of [Pl...

The reaction between a 1,2-ethanediamine solution of K4[Pb9] and a toluene solution of [Pl(PPh3)4] in the presence of crypt-222 leads to the formation of the platinum-centred Zintl ion fPt@PbI2]2-, the 207Pb NMR spectrum of which consists of a pseudo-triplet (•/2i>7pbi«pt = 3440 Hz).

(a)   What is the role of the crypt-222 in the reaction?


(b)  Sketch the appearance of the 2,)7Pb NMR spectrum, paying attention to the relative intensities of the components of the triplet. Explain how this signal arises, and indicate on your diagram where the value of /207pbi95pt is measured.


(c)   The 195Pt NMR spectrum of lPt@Pb12J2' is a non­binomial multiplet. Explain the origins of the coupling pattern. What is the separation (in Hz) of any pair of adjacent lines in the multiplet?


[Data: 207Pb, 22.1% abundant, 7=4; 195Pt, 33.8% abundant, 1=^]

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Solutions For Problems in Chapter 14