Problem

Solutions For An Introduction to Genetic Analysis Chapter 16 Problem 9P

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Solution 1

The sequences of wild-type and mutant are as follows:

Wild-type ….. 5' AAUCCUUACGGA 3'…..

Mutant …... 5' AAUCCUACGGA 3' …..

The type of mutation depicted in the above sequences is frame shift mutation.

The mutant has a deletion of one base (U) from the wild type sequence.

In frame shift mutation, the number of bases in the mutant sequence is not in multiples of 3 because of the deletion of one base. This will affect first stop codon in the sequence.

The reading frame is changed because of the deletion of one base and results in a completely different translation and the codons. So, the codons code for different amino acid from the original ones.

A frame shift mutation is produced by deletions or insertions of nucleotides in a Deoxyribonucleic acid (DNA) sequence.

In genetic diseases like Tay-sachs disease and Human Immune Virus (HIV) frame shift mutations are apparent.

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