Question

The Williamson ether synthesis between 2‑naphthol (MW 144.2 g/mol) and allyl bromide occurs in dichloromethane solution in the presence of the phase transfer catalyst, PhCH 2 ( Bu ) 3 NCl , and NaOH and produces allyl 2‑naphthyl ether (184.23 g/mol).

A reaction was performed in which 0.43 g of 2‑naphthol was reacted with a slight excess of allyl bromide to make 0.46 g of allyl 2‑naphthyl ether. Calculate the theoretical yield and percent yield for this reaction. Allyl bromide has a density of 1.40 g/mL .

Answer 1

. According to the condition given in question let us calculate mole of 9 - naphthol Number of moles = given mass molar mass = 0.439 144.2 g/mol No. of moles = 0.00298 mol NOW calculate the moles of Ally 1-2- Naphthyl ether from reaction = 0.00298 mol X = 0.00248 mol of Allyl 2 naphthyl ether Amount of Ally l-q- naphthyl ether = no. of moles x molao mass

0.00298 mol x 184.23 = 0.5499 These fose theoretical Vield = 10.5499 The percentage yield can be calculated by using the following formula Actual Yield x 100 Theoretical Yield 0.439 - x100 78.32 0.5499 Therefore percentage Vield = [78.32". theoretical vield = 10.54979
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