The problem statement, all variables and given/known data a ball is thrown straight down from the top of a 220 feet building with an initital velocity of -22ft/s
a ball is thrown upward at 64 feet per second from the top of an 80 feet high building. The height of the ball can be modeled by S(t) = -16t^2 + 64t + 80(feet), where t is the number of seconds after the ball is thrown. describe the graph model
A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2a.) at what time will the ball strike the groundb.) for what time t is the ball more than 128 feet above the ground?c.) when will the ball reach its highest peak? how high is it above the ground?
If a ball is thrown directly upward with a velocity of 80ft/s, its height (in feet) after t seconds is given by y=80t-16t^2. What is the maximum height attained by the ball?
If a ball is thrown straight up into the air with an initial velocity of 95 ft/s, it height in feet after t second is given by y=95t–16t2. Find the average velocity for the time period begining when t=1 and lasting(i) 01 seconds: (ii) 001 seconds:(iii) 0001 seconds:Finally based on the above results, guess what the instantaneous velocity of the ball is when t=1.
A baseball is thrown straight up from the rooftop 192 feet high. The function s(t)=16t^2+-64t+192 describes the ball's height above the ground,s(t), in feet, t seconds after it was thrown. How long will it take for the ball to hit the ground? Explain
if an object is thrown vertically upward with an initial
velocity of v, from an original position of s, the height h at any
time t is given by:
h = -16t^2 + vt + s
If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by h16t2 +vt+s (where h and s are in ft, t is in seconds and v...
A ball is thrown from the top of a building with an initial velocity of 23.7 m/s straight upward, at an initial height of 52.0 m above the ground. The ball just misses the edge of the roof on its way down, as shown in the figure. (a) Determine the time needed for the ball to reach its maximum height. s (b) Determine the maximum height. m (c) Determine the time needed for the ball to return to the height...
A ball is thrown vertically upward with an initial velocity of 48 feet per second. The distances (in feet) of the ball from the ground after t seconds is s=48-16t2. (a) At what time t will the ball strike the ground? (b) For what time t is the ball more than 32 feet above the ground?
If an object is thrown with a velocity of v feet per second at an angle of θ with the horizontal, then its flight can be modeled by, x = (v cos θ ) t and y = v (sin θ ) t - 16 t2 + h where t is in seconds and h is the object's initial height in feet above the ground. x is the horizontal position and y is the vertical position, and - 16 t2...
MY NOTES ASK YC 10. [0/0.83 Points] DETAILS PREVIOUS ANSWERS LARCALC11 2.2.096. A ball is thrown straight down from the top of a 480-foot building with an initial velocity of -27 feet per second. Use the position function below for free-falling objects. s(t) = 1612 + vot + 50 What is its velocity after 2 seconds? (2) = 91 X ft/s What is its velocity after falling 364 feet? VE