The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party\'s leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet\'s surface by means of a simple pendulum of length 1.13 m. She sets the pendulum swinging, and her collaborators carefully count 107 complete cycles of oscillation during 204 s. What is the result?
SOLUTION :
In 204 seconds 107 cycles are completed.
So, time taken for 1 cycle = 204/107 sec.
This time is termed as Time period, T.
=> T = 204/107 sec
For pendulum of length L ,
T = 2 π sqrt(L/g) where g is gravitational acceleration at the Pink Planet.
=> 204/107 = 2 π sqrt (1.13 / g)
=> sqrt(1.13 / g) = (204/107) / (2 π)
=> 1.13/g = ((204/107) / (2 π))^2 = 0.0.092073
=> g = acceleration due to gravity at Pink Planet :
= 1.13/0.0.092073
= 12.27 m/s^2 (ANSWER)
The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather...
The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party\'s leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet\'s surface by means of a simple pendulum of length 1.38 m. She sets the pendulum swinging, and her collaborators carefully count 1.00 × 102 complete cycles of oscillation during 212 s. What...
The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length m. She sets the pendulum swinging, and her collaborators carefully count complete cycles of oscillation during s. What is the result?
The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader-a physicist, naturally-immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length 1.44 m. She sets the pendulum swinging, and her collaborators carefully count 107 complete cycles of oscillation during 2.00 x 10 s. What...