Question

Assuming the lower arm has a mass of 2.8 kg and its CG is 12 cm from the elbow-joint pivot


Assuming the lower arm has a mass of 2.8 kg and its CG is 12 cm from the elbow-joint pivot, how much force must the extensor muscle in the upper arm exert on the lower arm to hold a 7.5 kg shot put (Fig. 12-7)?                   

                           
          

1000 N

                           
          

1500 N

                           
          

100 N

                           
          

500 N

                           
          

750


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Answer #1



Ok....So lets do the sum of the forces about the elbow joint.

Fm = Force of Muscle; Fe = Force Elbow; Fb = Force Ball

Sum Force about Joint = (-2.5)Fm + 12Fe + 30Fb = 0

(-2.5)Fm + 12(2.8) + 30(7.5) = 0

Fm = 103.44kg

Fm = 103.44 * 9.8 =1013.71N ROUND ABOUT

Do you understand why the -2.5 is negative?
Because I put the origin at the joint. So when you go left it is negative and when you go right it is positive.

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Answer #3

the force needed is

F = (m1 + m2) x g

where m1 = 2.8 kg,m2 = 7.5 kg and g = 9.8 m/s^2

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