Question

7. It takes 83 mL of a 0.45 M NaOH solution to neutralize 235 mL of an HCl solution. What is the concentration of the HCl solution? 8. It takes 12.5 mL of a 0.30 M HCl solution to neutralize 285 mL of NaOH solution. What is the concentration of the NaOH solution?

Answer 1

??? ASE ca un (Nor) = CXY = 0.45 mol/2x0.0832 = 0.03735 more of Nuoss . moks of Noot = 0.03735 more As more Nuosh renuires a more hen to neutralise. i moles of neu required= 0.03735 mile. volume of min = 235 mi = 0.235L - - (FACA = n men Vuel = 0.03335 more 0.235L = 0.1589 M - Molarini of nena 0.159 na = 0.16 na

I AS na av ninen) = 0.3 ml/L 0.0125 L = 0.00375 more i moly of Hen=0.00375 more . 0.00375 mole nen requires 0.00375 mole noon i mokes of wood = 0.00375 mole. rolume of woon = 285 m. = 3 n 0.2852 a c= 0.00375 more 0.285 L = 0.01315 m = 0.0132 ng ingolarity of Noah = 0.0132 na