Consider a simple pendulum: a bob on the end of a string. The length of the string (assumed massless) is 85 ?? and has a period of 1.62 ?. Assuming this pendulum is on another planet rather than Earth (and the angles are small), determine, a. The gravitational acceleration, near the surface of the planet. b. The angular frequency.
Consider a simple pendulum: a bob on the end of a string. The length of the...
Consider a simple pendulum consisting of a massive bob suspended from a fixed point by a string. Let T denote the time (period of the pendulum) that it takes the bob to complete one cycle of oscillation. How does the period of the simple pendulum depend on the quantities that define the pendulum and the quantities that determine the motion? [You need to perform a dimensional analysis to solve this one. Start by assuming T = k Inmpgq, where k...
5. What should you do to the length of the string of a simple pendulum to double its period? 7. The acceleration of gravity gets smaller as you increase your distance from the center of the Earth. For example, if you go to a height that is one earth radius above the surface of the earth the acceleration of gravity is 2.45 m/s² (g/4.0). Is the period of a pendulum longer or shorter? 8.A pendulum makes 42 cycles in 50.0...
Problem 1 (6 pts): A small bob of mass 0.4kg is attached to the end of a string of length 1.50 m to form a simple pendulum. It is displaced through an angle of 15.0° and then released at time t-0s. The angular position of the pendulum for small angles is described with: e) Sketch a θ vs. t graph for at least two cycles, starting at t-0s. Place numbers on the t-axis. Place a dot on the curve at...
What is the period (in s) of a simple pendulum of length 0.12 m and mass 0.31 kg near the surface of a planet where the gravitational acceleration is 11 m/s2? Enter a number with 2 digits behind the decimal point..
A certain simple pendulum consists of a small 750.0 ? bob that swings on the end of a 25.0 ?? string. The small amplitude of the oscillations of this pendulum decays to half its original value after 45.0 oscillations. The angular position of the pendulum as a function of time, ?(?), can be expressed as follows. ?(?) = ??0 ? − ??/2m cos(? ′ ? + ?) ??0 is the original angular amplitude. ? is the time, and ? is...
Part 1: (Theory) Simple Pendulum 1. Consider a mass m hanging from a string of length L that makes an angle with the vertical (shown below). Assume the string is massless and that the hanging object is a point mass. Use Newton's Second Law directly to show that the equation of motion for this simple pendulum can be written: (LO) = -mgsin(o), (1) dia where is the angular displacement of the pendulum from its vertical equilibrium position (and is a...
1. If placed at the surface of Earth, a physical pendulum has a period of 1.8 seconds. What will be the period of the same pendulum at the surface of the Moon (gMoon = 1.62 m/s2)? The period at the Moon's surface, T = Units in s 2. The same pendulum is placed at the surface of an unknown planet X. What is the free fall acceleration at the surface of this planet if the pendulum has a period of 1.17...
A simple pendulum is a massless string with a point mass at the end. The mass is 0.6 kg. The length of the pendulum is 0.1 m. The amplitude is 7.5°. What is the period of the pendulum?
If a fixed length simple pendulum is found to have three times the period on an unknown planet’s surface (compared to Earth), what is the acceleration due to gravity on that planet? Show your work.
A pendulum consists of a mass of 2 kg hanging from a massless string of length 1.1 m. It is being used on another planet. If the period of the pendulum is 1 s, what is the acceleration due to gravity on that planet, in units of m/s-2? Select one: a. 43 b. 87 c. 1.1 d. 11 e. 0.023