Question

I dont understand the process for this type of question. It has to do with determining the solubility in mL to achieve Purification of an Organic Compound. removing impurities to get compound A in pure form. If someone could show me the process step by step that would be great thank you.

ody Stall20 1 Does not react w/ compound Only dissolves at higher temp. o called large temp. coefficient 3) Only dissolves at a low called small temp. coefficient 4) low boiling point it higher temp. not low temp. dissolves at a lower temp, not high temp down to solid again recrystalization boil it cool it and it crystalizes * Compound in Solubility g/100 mL 25 10 80 100 1. 5 5 0 o o . 1 impurity impurity 2 partially son insoluble I 2 = 1.0g / so impurity & stays solid, you take it out then You're left with A and impurity 1 A = loa so in comparison to the table, I 1 = 1.00 4 12.0g up to 80g of a can be dissolved and up to 50g of Il. Both will L dissolve in solute. (100mL) Then if you cool at 25°, the compound A will crystallize 9.0g (be only 1. Og is soluble) and I l will still dissolve (be 1.5g is soluble). Then you filter and youre left will just A in pure form. yield = 100 * 9.0/12.0 = 75% le +

A= 10g

impurity 1= 1.0g partially soluble

impurity 2= 1.0g insoluble

the question is really how to seperate, and the next part of the question is how to maximize the yield by giving appropriate mL.

Answer 1

- 1. question :- 1 How to separate impurity from an Organic componi We have compound A = 1097 Impurity I = 1.0 Impurity 2 =1.09 Recrystalisation is one of the Isolation process of pure Organic Compound 1 let me explain with Real Life Example. | Let's say we have compound and Impurity tas salt . Impurify 2 as sand Let's assume compound A is soluble in water. e and salt also soluble in water. So, If we add water in compound having Impurity 1 and Impunity 2 After some time we will see that compound A + Impunity 1 is dissolved in water and there are no solid traces of it present. Only thing is there in solid is Impurity 2 ie sand. so, we filter out the water and separate the sand Like this . We removed impurity 2 from the comp.A. Now, filtered out water which contains compound A and salt If compound have lower boiling oint, We can do distillation.

Water and compound A will be distilled out in a separate Hask and salt will be remained in previous Hask. It's like evaporation of salt water In this case low boiling compound As es went off with water vapour Till now, we removed impurity 2 and Impurity ! - so we have pure compound A and solvent (Water) Due to different is boiling in points . We can distill out compound A also. water sand Scelt exe were Assumptions According to Impurities and compounds, solvent is - Selected in Here we selected water because we knew salt and kompound A is soluble in it In the giren Case we don't have to distil out. i compound A have. tout 250C tureezing point but Impurity I does not. Therefore compound . A can be separated out very Easily by decreasing the temperature.upto 25°c. Question: How to increase yield of compound A. 1 simple precautions should be taken to prevent 2 loss of product like first we dissolved compound A and Impurity 1 in solvent to separate out Impurity 2. Make sure theel Solven vapour should not escape. Stirmed Sting well.