Homework Answers
q1 = +Q and q3 = +3Q
force on q4 is along -x as q4 = -4Q
total force = k 3Q* -4Q / (3d)2 + k Q* -4Q / (1.5d)2 = -3.11kQ2 /d2
q2 = -2Q , force on q4 acs along the line joining q2 and q4
= k -2Q *-4Q / (1.52 + 1)d2 = 2.46kQ2 /d2
x -comp = +2.05 kQ2/d2
y-comp = -1.36 kQ2 /d2
Total x-comp of force on q4 = -3.11kQ2 /d2 +2.05 kQ2 /d2 = -1.06 kQ2 /d2
Total y-comp = -1.36 kQ2 /d2
direction of the force = arcTan( y/x) = arcTan(1.36/1.06) = 52.06o
The force acts in the 3-quadrant i.e. it makes 180 +52.06 = 232.06o with +x axis.
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