XYZ company is manufacturing two products A and B. Production is limited to 80 units of product A and 60 units of product B due to limited supply of raw material. Production of each of these products requires 5 units and 6 units of electronic components respectively. The electronic components are supplied by another manufacturer and the supply is limited to 600 units per day. The company has 160 employees, i.e., the labor supply amounting to 160 man days. The production of one unit of product A requires one man-day of labor the production of one unit of product B requires two man-days of labor. Each unit of these products is sold in the market at a profit of OR 50 and OR 80 respectively. Determine how many units of each product the company should produce to maximize profit. A) Formulate this linear programing problem. B) Find the optimal solution by graphical method and communicate your decision.
Question 1
Scenario 1- Fixed cost = $25000 Variable cost= $10 Price = $30
To breakevem $30x = $10x + 25000 where x is number of dolls sol
20x = 25000 . X = 1250 units
Scenario 2
Fixed cost = $17000 VC=$14 Price =$30
To breakeven 30x = 14x + 17000
16x= 17000 x = 1062.5
Question 2
Let number of units produced of A = a
Let number of units produced of B = b
Maximize = 50a + 80b
Condition 1 a <=80
Condition 2 b <=60
Condition 2 5a + 6b <=600
Condition 3 a + 2b <= 160
Solving for Condition 1 a=80; solving for condition 2 b=60 (Draw lines)
Solving for Condition 3 to get coordinates for graph 5a+6b=600; if a =0 then b = 100 and if b=0 a= 120
Solving for Condition 4 to gte coordinates for graph a=0 then b =80 and if b=0 a= 160
Solve for equations :
Multiply Condition 4 by 5
Condition 4 *5 5a +10b = 800
Less Condition 3 5a+ 6b = 600
4b = 200
b = 50 Putting value of B in Condition 3
5a= 600 - 300
a = 60
By given data of old BEP & new BEP
Breakeven point = Fixed cost / (Selling price – variable cost)
Old breakeven point = 25000/(30-10) = 1250
New breakeven point = 17000/(30-14) =1062.5 or 1063 units (rounding up)
This means the breakeven point will reduce by 1250-1063 = 187
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