Question

omnou (ap) + Fe 2+ 10 Mnoy (af) + F e 2 + ( ) ) to Mnoh +C204 + 2 ? ? + - 4 Cr Ost Noz (ap) y @ Cry 0,1 g + Fe or less 6 Noz tl y (@g) @P I Part A Copper nitrate Acids O Curs + Hellas) Cu (s) + NO3-) ③ Cub) + NO3 Cay) = Solve for Balanced Net lonic equation Bahrenfor find oxidizing Agent and Reducing Ag

Answer 1

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Ans:- 1 Fe 2+ + oxidation Mn Ou- → number Fe +2 Mr = +7 Fe 3+ + m₂ 2t. Fe = +3 mm + 2 " 5 Fe 2+ + Imno - 556 3 + 1 mm 27 now balancing. I and H we get, Sfect + Mnoy + 8H S Fe3+ + IMA2+ + 4H₂O ② This part is same as 1st as far as i am concerned. ③ Mnou + GO y 2 - + H+ mut + CO₂ + H2O Coz Oz 2 - + 300,- + 8H - 2 (6) 3+ + 3003 + 4H20 I'm writing the balanced equation after doing the same procedure as ② and balancing o and H. 6Feet + (20 2 - + 14Ht 2 Gr 3 + + 740 +6Fest I H₂Sou ③ 6NO3 +6H+ + i - IO₂ tong + 3H20. o Cut Ho - no reaction. Cu does not react with Hill or Cut 4 Hos o C (NO3)2 2ND 219) * 2420 14)