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Based on the ideal gas law, there is a simple equivalency that exists between the amount...

Based on the ideal gas law, there is a simple equivalency that exists between the amount of gas and the volume it occupies. At standard temperature and pressure (STP; 273.15 K and 1 atm, respectively), one mole of gas occupies 22.4 L of volume. What mass of methanol (CH3OH) could you form if you reacted 4.24 L of a gas mixture (at STP) that contains an equal number of carbon monoxide (CO) and hydrogen gas (H2) molecules?

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Answer #1

a valume of gas mixture - 4+24L males of gas present se to 424 L * 22:41 mal 20.189286 mal Since equal malecules of both gas

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