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A block of mass 0.240 kg is placed on top of a light


A block of mass 0.240 kg is placed on top of a light, vertical spring of force constant 5 200 N/m and pushed downward so that the spring is compressed by 0.094 m. After the block is released from rest, it travels upward and then leaves the spring. To what maximum height above the point of release does it rise? (Round your answer to two decimal places.) 

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Answer #1

Let the required height be h,

By energy conservation, initial spring energy = final gravitational potential energy

0.5 kx^2 = mgh

0.5*5200*0.094^2 = 0.24*9.8*h

h = [0.5*5200*0.094^2]/(0.24*9.8)

= 9.77 m answer

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