Question

Problem 23.29 (Multistep)

An accelerated electron
An electron is initially at rest. At time t1=0 it is accelerated upward with an acceleration of a= 1 × 1019 m/s2 for a very short time (this large acceleration is possible because the electron has a very small mass). We make observations at location A, x= 16 meters from the electron (see the figure).

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Part 1

(a) At time t2= 1 ns (1 × 10-9 s), what is the magnitude and direction of the electric field at location A due to the electron?

magnitude: N/C

direction:

to the left
upwards
downwards
to the right
zero field

the tolerance is +/-2%

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Part 2

(b) At what time t3 does the electric field at location A change?

seconds

(c) What is the direction of the electric field at location A at time t3?

downward
to the right
zero field
upward
to the left

the tolerance is +/-2%

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Part 3

(d) What is the magnitude of this electric field?

N/C

(e) A positively charged particle was initially at rest at location A. It is released from rest just after time t3. Which of the following are true just after time t3? (Select all that apply.)

The electric force on the positive charge is toward the electron.
The radiative magnetic field at location A is out of the page.
The positive charge begins to move because there is a force on it due to the radiative electric field.
The positive charge will never be affected by the radiative magnetic field, since the positive charge is always at rest.
The electric force on the positive charge due to the radiative electric field is upward.
There is a magnetic force to the right on the positive charge.Electron -----
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Answer #1

tzi Ins Magnitude og electic field E ao for = 9x109 x 1.6X10 - 16x16 = 5.62x 10-12 N/C towards left Direction Ans Ans b) rad

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