Homework Answers
Write the expression of heat flow through a conductor -
Q = k*A*ΔT / t --------------------------------------------------(i)
Where -
Q = 25.7 kW = 25.7 x 1000 = 25700 W
A = 0.819 m^2
ΔT = ?
t = 5.73 cm = 0.0573 m
k = 50.2 W/m·K
Put these values in expression (i) -
25700 W = 50.2W/m·K * 0.819m² * ΔT / 0.0573m
=> ΔT = (25700 * 0.0573) / (50.2 * 0.819) = 35.8ºC
So, temperature difference between the sides of the plate = 35.8ºC (Answer of second part)
Temperature gradient = ΔT/t = 35.8 / 0.0573 = 624.8 K/m (Answer of first part)
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