Question

Keep getting it wrong because I need the answer in picofarads (pF)

1. 0/2 points Previous Answers PSE6 26.AE.01. Example 26.1 Parallel-Plate Capacitor Problem A parallel-plate capacitor has an area A = 1.90 X 10^4 m- and a plate separation d = 1.26 mm. Find its capacitance. Strategy Use Equation 26.3. €0. Solution From Equation 26.3, we find the following. (1.90 x 10-4 m² = (8.85 x 10-12 C2/N. 1.26 x 10-3 m X PF Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. Exercise 26.1 Hints: Getting Started I'm Stuck If the plate separation is increased to 7.05 mm, find the capacitance. C = pF

Answer 1

$C=\frac{A\varepsilon _{0}}{d}=$$C=\frac{A\varepsilon _{0}}{d}=\frac{1.9*10^{-4}*8.854*10^{-12}}{1.26*10^{-3}}=1.335\ pF$

$C=\frac{A\varepsilon _{0}}{d}=\frac{1.9*10^{-4}*8.854*10^{-12}}{7.05*10^{-3}}=0.2386\ pF$