Homework Answers
(25.a)
We know that, Grahm's law of diffusion,
rate ∝ 1/√M
where,
M = Molar Mass
r12CO2/r13CO2 = √(45/44)
r12CO2/r13CO2 = 1.011
(25.b)
As rate of diffusion is inversaly proportional to molar mass.
Hence, lighter molecule 12CO2 diffuse at faster rate.
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