Question

5. For the previous question, using the equation for Q=rxn energy=[Mass(producs)-Mass(Reactants)]*931.5 MeV/amu, calculate th
4, Neptunium - 237. Write decay for a, b, a, a D 287 Np a h He + 233 Pa B (3) 233 0 a Г) 11, Th le + 28 The не на ва —
this the answer to the previous question (4). problem 5 is what i need help with and its based off the answer in problem 4. thank you!
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A: seachon energy (Mass cproducts)- Mass (aeactants)]931.5 Meamu seSues decay Neptunium 937 Q33 Pa 237 NP 44 He o decay 93 4.

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this the answer to the previous question (4). problem 5 is what i need help with...
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