Question

31. For the reaction: 302(g) 203(g); at equilibrium 0.80g of O2 and 0.24g of Oz was found at 0.20 atm pressure. Calculate the

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Answer #1

48 - 302 (9) = 203 (g} moles of O, - Mass in gm. 0.8 - Molar Mass - 32=0.025 Melee of Oz - 0.24, 5x103 total Moles= 0.025 +0.

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show your work please... 31. For the reaction: 302(g) 203(g); at equilibrium 0.80g of O2 and...
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