3.059)
x | P(x) | xP(x) | x2P(x) |
-2 | 1/8 | -0.250 | 0.500 |
-1 | 1/4 | -0.250 | 0.250 |
0 | 1/4 | 0.000 | 0.000 |
1 | 1/4 | 0.250 | 0.250 |
2 | 1/8 | 0.250 | 0.500 |
total | 0.000 | 1.500 | |
E(x) =μ= | ΣxP(x) = | 0.0000 | |
E(x2) = | Σx2P(x) = | 1.5000 | |
Var(x)=σ2 = | E(x2)-(E(x))2= | 1.500 |
from above mean μ=0
and variance σ2 =3/2
3.060)
x | P(x) | xP(x) | x2P(x) |
1 | 16/21 | 0.762 | 0.762 |
2 | 4/21 | 0.381 | 0.762 |
3 | 1/21 | 0.143 | 0.429 |
total | 1.286 | 1.952 | |
E(x) =μ= | ΣxP(x) = | 1.2857 | |
E(x2) = | Σx2P(x) = | 1.9524 | |
Var(x)=σ2 = | E(x2)-(E(x))2= | 0.299 |
mean μ=1.286
variance σ2 =0.299
Help please Assignment Assignment> open Assignment ASSIGNMENT R 3.4 Problem 3.059 dPractice Reading Incorrect An Dom...
Assignment Assignment> open Assignment ASSIGNMENT R 3.4 Problem 3.062 dPractice Reading Determine the mean and variance of the random variable with the following probability mass function. Hint: Use the formula for the sum of the infinite series 흙 a'-T,a, where 1 . teview Score Give exact answers in form of fraction. Oblective Mean Moble Site Variance Click if you would like to Show Work for this question: Qen Show Werk Question Attempts: of 3sed SAVE FOR LATERSUBHIT ANSWER
Assignment Assignment open Assignment Problem 3.045 Problem 3,039 In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume that the probability that a wafer passes the test is 0.6 and that wafers are independent. Determine the cumulative distribution function of the number of wafers from a lot that pass the test at specified values. Round your answers to three decimal places (e.g. 98.765). Problem 3.046 Review Score Obiectiv Moble...
Assignment Assignment open Assignment Problem 3.051 Problem 3,039 Preblem 3.045 The following function is cumulative distribution function. F(X)-0.75 35x55 -5sx< 35 Review Score Review Results by Stuew Obiectiv Moble Site Determine the requested probabilities. Round your answers to two decimal places (e.g. 98.76) P(X S 45) P(X <0) Stitatta Tabies and Charts Click if you would lske to Show Work for this question peShow W Question Attempts: O of 3 used SAVE FOR LATER SUBMIT ANSWER
Assignment Assignment open Assignment Problem 3.049 Problem 1.039 Verify that the following function is a cumulative distribution function. Review Score Obiectiv Round your answers to 1 decimal place (e.g. 98.7). Determine: P(X 3)= P(X S 2) Moble Site 2) P(X > 2)- Statist Table1 and 다arts Click if you would like to Show Work for this question: n Show Werk Question Attempts of 3 usedSAVE FOR LATERSUBHIT ANSWER
WHlav DLUIS Weygandt, Managerial Accounting, Be WileyPLUS Help System Announcements CALCULATOR PRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES Unit 8 Lab 330 1902A Question 1 Question 2 Question 3 Question 2 Lewis Company's standard labor cost of producing one unit of Product DD is 3.70 hours at the rate of $10.60 per hour. During August, 40,400 hours of labor are incurred at a cost of $10.75 per hour to produce 10,800 units of Product DD. (a) Compute the total labor variance....
gomerY Help I System Announcements en Assignment Problem 4.200 Your answer is partially correct. Try again. The time between process problems in manufacturing ine is exponentialy distributed with a mean of 37 days (a) Whet is the expected time until the fourth problem? (b) What is the probability that the time until the fourth problem exceeds 148 days? 368 by Studythe answer to 3 decimal places.) Click if you would like to Show Work for this question: Open Show Work...
Assignment Assignment > Open Assignment PRINTER VERSION BACK NEXT Wiley PLUS Problem 13-4 a-b Marinis Corporation is considering buying a brand new machine and has gathered the following data: ASSIGNMENT RESOURCES ACC212 Lab #9 Brief Exercise 13.1 Exercise 13.16 WileyPLUS Problem 13-7 a-b Brief Exercise 13.6 WileyPLUS Problem 13-4 a-b Investment Estimated life Estimated annual cash inflows Estimated annual cash outflows $104,100 5 years $29,500 $10,300 Salvage value for the machine is estimated to be zero. Review Score Review Results...