Question

moles of Mg and balanced chenical reactions with phases

Name: Haytry Stonavina Data Section #: Date: Collecting hydrogen gas from the reaction of Mg with HCI TO HG Atmospheric pressure in Hg) Mass Mg ribbon Volume Ha collected (ml) Temperature of water (°C) 11 Partial pressure of H: Temperature of water (K) Trial 1 Trial 2 Trial 3 1 7600 nano 700 ruilo osolog .059 1.089 sime 46 ML I de ML 22°C 22°C 12°c 19.8 mmHg 19.8 amHg 19.8 mm Hal 760 mmHg 760 mmuo 790 mmHg 1740 mmie 740 mag 740 mm Hg 295 295 295 OSE .OHO oloce 0.0020 1.0019 0.0027 . o mes 0.00 al 0.co33 80% 90.5% 81.8% o Moles of Mg Theoretical moles of H Percent yield Calculations (show for trial 1 only) Balanced chemical reaction with phases: Atmospheric pressure (mmHg): 700 MOHO Partial pressure Hz (use Dalton's Law): PH2 = patm-phao=

Answer 1

1. Balanced chemical reaction is :

Mg(s) + 2HCl (aq) ---> MgCl₂(aq) + H₂(g)

2. Moles of Mg:

Trail 1:

Mass of Mg = 0.060 g

Molar mass of Mg = 24.3 g/mol

Moles of Mg = mass/ Molar mass = 0.06 g/ (24.3 g/mol) = 2.47 *10^-3 mol

Trail 2:

Mass of Mg = 0.05 g

Molar mass of Mg = 24.3 g/mol

Moles of Mg = mass/ Molar mass = 0.05 g/ (24.3 g/mol) = 2.06 *10^-3 mol

Trail 3:

Mass of Mg = 0.08 g

Molar mass of Mg = 24.3 g/mol

Moles of Mg = mass/ Molar mass = 0.08 g/ (24.3 g/mol) = 3.29 *10^-3 mol