Question

han MenuContents Grades Course Contents >> ... > Torque - 1 Probs » Chapter 8, Problem 26 • Timer Notes evaluate Feedback A 1270 N uniform boom is supported by a cable perpendicular to the boom, as seen in the figure below. HHHHHH m The boom is hinged at the bottom, and an M = 2130 N weight hangs from its top. Assume the angles to be a = 62.00 and 0 = 90.0" - . Find the tension in the supporting cable. Submit Answer Tries 0/10 Find the x-components of the reaction force exerted on the boom by the hinge choose to the right as pestive) Submit Answer Tries 0/10 Find they components of the reaction force exerted on the boom by the hinge (chonse upwards as positive, Submit Answer Tries 0/10 Send This discussion is closed. A 11:21

Answer 1

Solution: Wo=1270N W = 2130 N X = 63.0*, 0 =90.0*__ o = 27.0° т consider tosque about pivot, Net torque =0. T 3 1 2 = Wb & cosx + mg e cosx ay + W) Cs & 1270 +2130.) (as 63.0" r Te - 2 T = 1673.7 N 2. Efa=0 fx = + los = T cos (90.0-0) Fr = T as 27.0° = 149103 N 3. {Fy =0 Fy + T sino = Woting Fy = 1270+ 2130 - T sin 27.0° = 2640.2 N