Question
a person steps out of the shower and dries off. the person's skin with an emissivity of 0.70 has a total area of 1.2 m^2 and a temperature of 33°C. what is the net rate at which energy is lost to the room through radiation by the naked person if the room temperature is 24°C?

TIDLALLLL LA LILIILI JIAIL WHITUURE DOING WHAT PUU VUI THEORY), AND SHOW ALL WORK. 1. A person steps out of the shower and
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Answer #1

Solution : Using Stefans law, e EE EO (TY-To) Also, H = EXA = EOA (TY_.4) H = 7(5-67 x 100%) 112) [1300%(297) Solving the a

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