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3. b. 5 Derive the Eh Vs pH relationship for the following reaction under standard conditions. Pb09) + 4H* +2e=Pb2+ 2H20 E =
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Eh vs PH relation.ship The Nernst equaltm for electro chemi cal cel is qiven by Yeducrd specieS RT n E E reacdant oxidised Spwe know E 455 v (aven So, relatimship betueen En and pt becomes En 455 00148 log [P 0-0592 þH Pe 2R2 NeYnst equatim Here n1 EWe Know logksP 2.303RT Here n 2 at 25 2313RT 2.303 RT o E 2.303 RT -15.8 20-0592 O-0592 -15-3 O 4676 The Half-reacifoMs are RMo2++4H20, Mnoq8Ht +5e Nernst equalion E 51 mHere n5) Mn2r] -G8Mn-[4]8 E E 00592 5 Mn2 O-U592 5 E-00592 Eh=51 001g tgTMnq 0-0If you like the answer please give a thumbs up ?.

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