Question

chap07-P3 Please write the answer neatly for a thumps up, thank you!

Flying Circus of Physics On August 10, 1972, a large meteorite skipped across the atmosphere above the western United States and western Canada, much like a stone skipped across water. The accompanying fireball was so bright that it could be seen in the daytime sky and was brighter than the usual meteorite trail. The meteorite's mass was about 3.9 x 106 kg; it's speed was about 15 km/s. Had it entered the atmosphere vertically, it would have hit Earth's surface with about the same speed. (a) Calculate the meteorite's loss of energy (as a positive number, in joules) that would have been associated with the vertical impact. (b) Express the energy as a multiple of the explosive energy of 1 megaton of TNT, which is 4.2 x 1015 J. (c) The energy associated with the atomic bomb explosion over Hiroshima was equivalent to 13 kilotons of TNT. To how many Hiroshima bombs would the meteorite impact have been equivalent? (a) Number T4.39 Units (b) Number Units This answer has no units Units This answer has no units (c) Number 8.00

Answer 1

| Answer Geven that m=3.9x106, V=L5 km/s : V=15000 m/s Energy lasses in impact - mv = x3,9x106x (18000) = 4.3875 X 104 =438.8x10?J. - In megaton of ThiT € - 438.8x102 imegaton of TNT =462x1d5J. 2X10'5 = 0.1045 megaten of TNT. 13 kiloton of tot = 5.439x1013 J. Total No = 438 •8x102 5.439103 = 8.068 Hiroshima bombs