Homework Answers
a. Variances are homogeneous, from the Levene statistics = 0.8 which is not significant.
b.
|
Group |
Mean |
Standard Error |
|
1 |
38 |
5.477 |
|
2 |
32 |
3.464 |
|
3 |
24.17 |
4.309 |
C. Means are not equal (i.e. there is significance difference between all three means)
|
ANOVA |
|||||
|
Sum of Squares |
df |
Mean Square |
F |
Sig. |
|
|
Between Groups |
656.125 |
2 |
328.062 |
16.769 |
.000 |
|
Within Groups |
410.833 |
21 |
19.563 |
||
|
Total |
1066.958 |
23 |
|||
e.
the estimated value for the contrast 
as
given below.
Estimated value for the given contrast is -4.37 with Standard error 1.986
Add Answer to:
d) OBTAIM A CONFIDENCE INTERVAL 4i FOR THİS CONTRAST 31.0 5.0 29.0 3.0 2.0 20.0
Days Status 29.0 1 42.0 1 38.0 1 40.0 1 43.0 1 40.0 1 30.0 1...
Days Status
29.0 1
42.0 1
38.0 1
40.0 1
43.0 1
40.0 1
30.0 1
42.0 1
30.0 2
35.0 2
39.0 2
28.0 2
31.0 2
31.0 2
29.0 2
35.0 2
29.0 2
33.0 2
26.0 3
32.0 3
21.0 3
20.0 3
23.0 3
22.0 3
Pr d) OBTAIN A 9 CONFIDENCE INTERVAL FOR THİS CONTRAST.
4i 4.0 cm 2.0 cm +42 43 3.0 cm 3.0 cm In the figure above, q1...
4i 4.0 cm 2.0 cm +42 43 3.0 cm 3.0 cm In the figure above, q1 = 6.49 nC, q2 = 13.0 nC, and q3 = 13.0 nC. If the net force on q1 is 0, then what would q be? Answer:
SnowGeese File: Trial Diet WtChange DigEff ADFiber 1 Plants -6.0 0.0 28.5 2 Plants -5.0 2.5 ...
SnowGeese File:
Trial Diet WtChange
DigEff ADFiber
1 Plants -6.0 0.0
28.5
2 Plants -5.0 2.5
27.5
3 Plants -4.5 5.0
27.5
4 Plants 0.0 0.0
32.5
5 Plants 2.0 0.0
32.0
6 Plants 3.5 1.0
30.0
7 Plants -2.0 2.5
34.0
8 Plants -2.5 10.0
36.5
9 Plants -3.5 20.0
28.5
10 Plants -2.5 12.5
29.0
11 Plants -3.0 28.0
28.0
12 Plants -8.5 30.0
28.0
13 Plants -3.5 18.0
30.0
14 Plants -3.0 15.0
31.0
15 Plants -2.5 ...
The position of a particle is described by the function x = 3.0 t2 + 5.0...
The position of a particle is described by the function x = 3.0 t2 + 5.0 t + 3.0 (m). Determine the average velocity (in m / s) for the time interval t1 = 2.0 s and t2 = 4.0 s.
5.0 69 4.5 68 3.5 3.0 $ 2.5 2.0 67 65 64 63 61 1.0 0.5...
5.0 69 4.5 68 3.5 3.0 $ 2.5 2.0 67 65 64 63 61 1.0 0.5 3.0 3.5 4.0 4.5 5.0 5.5 6.0 6.5 7.0 UNEMPLOYMENT RATE (Percent)
2. (10 pts) Consider the figure below with I-5.0 A, 2 2.0 A and I 3.0...
2. (10 pts) Consider the figure below with I-5.0 A, 2 2.0 A and I 3.0 A. (a) Deternine the integral B di -B, d clockwise around loop a. (b) Determine the integralfsd/.? dlclockwise around loopb. (c) Determine the integral f?agAdlclockwise around loop e (d) Determine the integral f? d'efadl counter-clockwise around loop d 2
A 2.0-kg mass moving at 5.0 m/s suddenly collides head-on with a 3.0-kg mass at rest....
A 2.0-kg mass moving at 5.0 m/s suddenly collides head-on with a 3.0-kg mass at rest. If the collision is perfectly inelastic, what is the speed of the masses just after the collision? 2.5 m/s 10 m/s 2.0 m/s 0 m/s, since the collision is inelastic
16 For the displacement vectors a-(3.0 m)^ + (4.0 m)^ and B. (5.0 m)i(-2.0 m)j, give...
16 For the displacement vectors a-(3.0 m)^ + (4.0 m)^ and B. (5.0 m)i(-2.0 m)j, give a +bin Figure 3-28 Problem 15. (a) unit-vector notation, and as (b) a magnitude and (c) an angle (rela- tive to i). Now give b - a in (d) unit-vector notation, and as (e) a magnitude and (f) an angle
2.0 kg 3.0 kg PROBLEM 4-8 points 2.0 kg In case 1 and case 2, the...
2.0 kg 3.0 kg PROBLEM 4-8 points 2.0 kg In case 1 and case 2, the boxes are 5.0 kg 5.0 kg 3.0 kg subjected to the same constant force F F directed to the right. The surface is frictionless. Case 1 Case 2 [2 points] (a) Draw one free-body diagram, and use it to come up with an expression for the acceleration of the system. Be clear what you are drawing the free-body diagram of. [2 points] (b) For...
Chapter 15 in the textbook reviews Web 2.0 and Web 3.0. However, from the Week Three...
Chapter 15 in the textbook reviews Web 2.0 and Web 3.0. However, from the Week Three Lecture slides for Chapters 15 and 16 we know that technology is already bordering on Web 5.0. Match each item below to its Web x version. - A. B. C. D. Social Networks - A. B. C. D. Artificial Brain ...
Days Status
29.0 1
42.0 1
38.0 1
40.0 1
43.0 1
40.0 1
30.0 1
42.0 1
30.0 2
35.0 2
39.0 2
28.0 2
31.0 2
31.0 2
29.0 2
35.0 2
29.0 2
33.0 2
26.0 3
32.0 3
21.0 3
20.0 3
23.0 3
22.0 3
Pr d) OBTAIN A 9 CONFIDENCE INTERVAL FOR THİS CONTRAST.
4i 4.0 cm 2.0 cm +42 43 3.0 cm 3.0 cm In the figure above, q1 = 6.49 nC, q2 = 13.0 nC, and q3 = 13.0 nC. If the net force on q1 is 0, then what would q be? Answer:
SnowGeese File:
Trial Diet WtChange
DigEff ADFiber
1 Plants -6.0 0.0
28.5
2 Plants -5.0 2.5
27.5
3 Plants -4.5 5.0
27.5
4 Plants 0.0 0.0
32.5
5 Plants 2.0 0.0
32.0
6 Plants 3.5 1.0
30.0
7 Plants -2.0 2.5
34.0
8 Plants -2.5 10.0
36.5
9 Plants -3.5 20.0
28.5
10 Plants -2.5 12.5
29.0
11 Plants -3.0 28.0
28.0
12 Plants -8.5 30.0
28.0
13 Plants -3.5 18.0
30.0
14 Plants -3.0 15.0
31.0
15 Plants -2.5 ...
5.0 69 4.5 68 3.5 3.0 $ 2.5 2.0 67 65 64 63 61 1.0 0.5 3.0 3.5 4.0 4.5 5.0 5.5 6.0 6.5 7.0 UNEMPLOYMENT RATE (Percent)
2. (10 pts) Consider the figure below with I-5.0 A, 2 2.0 A and I 3.0 A. (a) Deternine the integral B di -B, d clockwise around loop a. (b) Determine the integralfsd/.? dlclockwise around loopb. (c) Determine the integral f?agAdlclockwise around loop e (d) Determine the integral f? d'efadl counter-clockwise around loop d 2
A 2.0-kg mass moving at 5.0 m/s suddenly collides head-on with a 3.0-kg mass at rest. If the collision is perfectly inelastic, what is the speed of the masses just after the collision? 2.5 m/s 10 m/s 2.0 m/s 0 m/s, since the collision is inelastic
16 For the displacement vectors a-(3.0 m)^ + (4.0 m)^ and B. (5.0 m)i(-2.0 m)j, give a +bin Figure 3-28 Problem 15. (a) unit-vector notation, and as (b) a magnitude and (c) an angle (rela- tive to i). Now give b - a in (d) unit-vector notation, and as (e) a magnitude and (f) an angle
2.0 kg 3.0 kg PROBLEM 4-8 points 2.0 kg In case 1 and case 2, the boxes are 5.0 kg 5.0 kg 3.0 kg subjected to the same constant force F F directed to the right. The surface is frictionless. Case 1 Case 2 [2 points] (a) Draw one free-body diagram, and use it to come up with an expression for the acceleration of the system. Be clear what you are drawing the free-body diagram of. [2 points] (b) For...
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