What is the percent by mass of oxalate ion in a 0.291 g sample of the iron salt that took 20.91 mL of 0.02073 M potassium permanganate to titrate to a light pink endpoint?
What is the percent by mass of oxalate ion in a 0.291 g sample of the...
QUESTION 5 What is the percent by mass of oxalate ion in a 0.175 g sample of the iron salt that took 16.37 mL of 0.02004 M potassium permanganate to titrate to a light pink endpoint.
QUESTION 3 What is the percent by mass of sodium oxalate in a 0.853 g sample that took 17.81 mL of 0.03178 M potassium permanganate to titrate to a light pink endpoint? Answer could be greater than 100%
What is the percent by mass of sodium oxalate in a 0.614 g sample that took 20.96 mL of 0.03513 M potassium permanganate to titrate to a light pink endpoint?
BACKGROUND: Synthesis of Potassium Iron
(III) Oxalate Hydrate Salt
The iron(II) ions from
Fe(NH4)2(SO4)2•6H2O
will be precipitated as iron(II) oxalate.
Fe^2+(aq) + C2O4^2-(aq) --> FeC2O4 (s)
The supernatant liquid, containing the ammonium and sulfate
ions, as well as excess oxalate ions and oxalic acid will be
decanted and discarded. The solid will then be re-dissolved and the
iron(II) ions will be oxidized to iron(III) ions by reaction with
hydrogen peroxide.
2Fe^2+(aq) + H2O2(aq) --> 2Fe^3+(aq) +2 OH^ - (aq)
The...
The formate ion, (CHO2-), is related to the acetate ion and forms ionic salts with many metal ions. Assume that 11.874 g of M(CHO2)2 (where M represents the atomic symbol for a particular metal) are dissolved in water. When a solution of 0.300 M sodium sulfate is added, a white precipitate forms. The sodium sulfate solution is added until no more precipitate forms, then a few excess milliliters are added. The precipitate is filtered, washed, and dried. It has a...
1. Calculations Given the following data, determine the % by mass of oxalate (C2O42-) in a sample of an iron oxalate complex with the general formula Kz[Fex(C2O4)y].wH2O. The reaction between oxalate and permanganate is as follows: 6H+ + 5(COOH)2 + 2MnO4- → 10CO2 + 2Mn2+ + 8H2O m(iron oxalate complex) used for titration = 0.100 g C(KMnO4) standard solution = 0.0200 M M(C2O42-) = 88.02 g mol-1 Titre volume = 10.18 mL Enter your answer to 3 significant figures. 2....
i need help answering the table by tonight for my test!! thank
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Trial 1 Prelaboratory Assignment 1. What is the primary standard used in this experiment? What is the molar mass of the primary standard? 2. Use the chemical formula for the primary standard to write the chemical reaction for the standardization of potassium permanganate. 3. What will indicate the endpoint of the titration? 4. A 0.495 g sample of iron containing salt required 20.22 mL of 0.0194 M...
Both the oxalate ligands and the vanadium are oxidised by the KMnO4 with the oxalate decomposing and leaving the system as CO2(g). Therefore, the first titration step titrates both the oxalate and the vanadium. 0.3g of the complex salt was dissolved in 60ml of H2SO4 (2M). This solution was diluted to 100ml with distilled water. Take 25ml aliquot and heat the solution to 80 oc. Titrate this hot solution with potassium permanganate 0.01M until the bright pink colour is first...
A sample of an Iron Oxalato complex salt weighting 0.13 grams requires 31.27 mL of 0.013 M KMnO4 to turn the solution a very light pink color at the quivalence point. 1.Calculate the number of moles of KMnO4 added. 2. Calculate the number of moles of C2O42− in the sample of the oxalate salt. 3.Calculate the number of grams of C2O42− in the sample. 4. Calculate the percent weight of C2O42− in the original Iron Oxalato Complex salt sample.
A 0.495 g sample of iron containing salt required 20.22 mL of 0.0194 M permanganate solution to reach the endpointof a titration. What is the percent of iron (55.845 g/mol) in the salt? Work shown please